拓扑第四课 |
拓扑第四课
Product space revisit
Let represent the cartesian product (笛卡尔积) of
1.Box topology
basis
2.Product topology
subbasis
当 为有限集时,1与2一致;一般情况下,1细于2。
Theorem
Both 1 and 2, if is a subspace of , is a subspace of .
Both 1 and 2, if each space is Hausdorff, is Hausdorff.
why 2
Both 1 and 2, if ,then
why
Only 2. Let be given by ,while is called the coordinate function.Then is continuous iff. is continuous, .
When 1, try to find contradiction by
Quotient topology
(商拓扑)
quotient map
def
A surjective map is said to be a quotient map if
a subset is open in Y iff. is open in X.
a quotient map is sure to be continuous
open map
def
each open set maps to an open set
close map
def
each closed set maps to an closed set
Theorem
If a surjective cont. map p is open or closed, p is a quotient map.
Bijective quotient map is a homeomorphism
A is a subset of X, then a retraction of X onto A is a cont. map s.t. r(a)=a, it's a quotient map.
composition(复合) of quotient maps is quotient
Def
If is a surjection, then there is exactly one topology to make p a quotient map.It's called the quotient topology induced by p.
Just make sure that
quotient space
Let be a partition(分划) of X,p is the cannonical projection(正则映射)
The quotient topology induced by p on is called a quotient space